Research talk:Teahouse long term new editor retention/Work log/2016-04-13
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Wednesday, April 13, 2016
[edit]Double checking how many dates during both invites sample periods there are where invites were NOT sent.
#for TH2 (October 20 2014 - January 12 2015)
SELECT s_day from
(
SELECT ADDDATE('2014-10-20', INTERVAL @i:=@i+1 DAY) AS s_day
FROM (
SELECT a.a
FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
) a
JOIN (SELECT @i := -1) r1
WHERE
@i < DATEDIFF('2015-01-12', '2014-10-20')
) as all_dates where s_day not in (select distinct(date(sample_date)) from th_retention_sample);
Output:
2014-10-23 2014-10-27 2014-11-06 2014-11-12 2014-11-21 2014-11-23 2014-11-24 2014-12-06 2014-12-10 2014-12-15 2014-12-18 2014-12-21 2015-01-08 2015-01-09 #14 days where invites were not sent
#for TH3 (November 2 2015 - December 14 2015)
SELECT s_day from
(
SELECT ADDDATE('2015-11-02', INTERVAL @i:=@i+1 DAY) AS s_day
FROM (
SELECT a.a
FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
) a
JOIN (SELECT @i := -1) r1
WHERE
@i < DATEDIFF('2015-12-14', '2015-11-02')
) as all_dates where s_day not in (select distinct(date(sample_date)) from th_retention_sample_2);
Output:
2015-12-12 2015-12-13 #2 days where invites were not sent